Determine the peak value of the applied voltage and the current if the ac source is to deliver the same power to the load.
330 Views • Posted: 3 years
Solved, Closed
The 120-V dc source of Fig. 1(a) delivers
3.6 W to the load. Determine the peak value of the applied voltage
(Em) and the current (Im) if the ac source Fig. 1(b) is to
deliver the same power to the load.
3 Answers
$$P_{dc} = {V_{dc} I_{dc}}\\I_{dc} ={ P_{dc} \over V_{dc} } = {3.6W \over 120 V} = 30mA\\I_m = 1.414 I_{dc}\\ I_m = 1.414(30mA)\\ = 42.42mA\\$$
$$E_m = 1.414 E_{dc} = 1.414 (120) = 169.6V$$
$$P_{dc} = {V_{dc} I_{dc}}\\I_{dc} ={ P_{dc} \over V_{dc} } = {3.6W \over 120 V} = 30mA\\I_m = 1.414 I_{dc}\\ I_m = 1.414(30mA)\\ = 42.42mA\\$$
$$E_m = 1.414 E_{dc} = 1.414 (120) = 169.6V$$
$$P_{dc} = {V_{dc} I_{dc}}\\I_{dc} ={ P_{dc} \over V_{dc} } = {3.6W \over 120 V} = 30mA\\I_m = 1.414 I_{dc}\\ I_m = 1.414(30mA)\\ = 42.42mA\\$$
$$E_m = 1.414 E_{dc} = 1.414 (120) = 169.6V$$
Do you want to say or ask something?