Logarithm
What is logarithms
The use of logarithms in industry is so extensive that a clear understanding of their purpose and use is an absolute necessity. At first exposure, logarithms often appear vague and mysterious due to the mathematical operations required to find the logarithm and antilogarithm using the longhand table approach that is typically taught in mathematics courses. However, almost all of today’s scientific calculators have the common and natural log functions, eliminating the complexity of applying logarithms and allowing us to concentrate on the positive characteristics of the function.Basic Relationships
Let us first examine the relationship between the variables of the logarithmic function. The mathematical expression$$N=(b)^{x}$$
$$\begin{aligned}100 &=(10)^{2} \\27 &=(3)^{3} \\54.6 &=(e)^{4} \quad \text { where } e=2.7183\end{aligned}$$
$$1200=(10)^{x}$$
$$x=\log _{10} 1200=\mathbf{3 . 0 7 9}$$
$$10^{3.079}=1200$$
$$\log _{e} x=2.3 \log _{10} x$$
Some Areas of Application
The following is a short list of the most common applications of the logarithmic function:- This chapter will demonstrate that the use of logarithms permits plotting the response of a system for a range of values that may otherwise be impossible or unwieldy with a linear scale.
- Levels of power, voltage, and the like, can be compared without dealing with very large or very small numbers that often cloud the true impact of the difference in magnitudes.
- A number of systems respond to outside stimuli in a nonlinear logarithmic manner. The result is a mathematical model that permits a direct calculation of the response of the system to a particular input signal.
- The response of a cascaded or compound system can be rapidly determined using logarithms if the gain of each stage is known on a logarithmic basis. This characteristic will be demonstrated in an example to follow.
$$\begin{array}{l}\log _{10} 1 / 2=\log _{10} 0.5=-0.3 \\\log _{10} 1 / 10=\log _{10} 0.1=-1\end{array}$$
$$\log _{10} a b=\log _{10} a+\log _{10} b$$
$$\log _{10} \frac{a}{b}=\log _{10} a-\log _{10} b$$
$$\log _{10} a^{n}=n \log _{10} a$$
Example 1: Evaluate each of the following logarithmic expressions:
a. $ \log _{10} 0.004 $
b. $ \log _{10} 250,000 $
c. $ \log _{10}(0.08)(240) $
d. $ \log _{10} \frac{1 \times 10^{4}}{1 \times 10^{-4}} $
e. $ \log _{10}(10)^{4} $
Solution:
a. $ -2.398 $
b. $ +5.398 $
c.
d.
e.
a. $ \log _{10} 0.004 $
b. $ \log _{10} 250,000 $
c. $ \log _{10}(0.08)(240) $
d. $ \log _{10} \frac{1 \times 10^{4}}{1 \times 10^{-4}} $
e. $ \log _{10}(10)^{4} $
Solution:
a. $ -2.398 $
b. $ +5.398 $
c.
$$ \log _{10}(0.08)(240)=\log _{10} 0.08+\log _{10} 240=-1.097+2.380 =1.283 $$
$$ \begin{aligned} \log _{10} \frac{1 \times 10^{4}}{1 \times 10^{-4}} &=\log _{10} 1 \times 10^{4}-\log _{10} 1 \times 10^{-4}=4-(-4) \\ &=8 \end{aligned} $$
$$ \log _{10} 10^{4}=4 \log _{10} 10=4(1)=4 $$
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