Self Inductance
For brevity, the prefix self is usually dropped. Inductance is measured in henries (H), after the American physicist Joseph Henry.
Inductors are coils of various dimensions designed to introduce
specified amounts of inductance into a circuit. The inductance of a coil
varies directly with the magnetic properties of the coil. Ferromagnetic
materials, therefore, are frequently employed to increase the inductance
by increasing the flux linking the coil.
A close approximation, in terms of physical dimensions, for the
inductance of the coils of [Fig. 1] can be found using the following
equation:
where N represents the number of turns; $\mu$, the permeability of the core
(recall that $\mu$ is not a constant but depends on the level of B and H since $\mu = B/H$); $A$, the area of the core in square meters; and $l$, the mean length of the core in meters.
Substituting $\mu = \mu_r \mu_o$ into Eq. (1) yields
and
where $L_o$ is the inductance of the coil with an air core. In other words,
the inductance of a coil with a ferromagnetic core is the relative permeability of the core times the inductance achieved with an air core. Equations for the inductance of coils different from those shown above can be found in reference handbooks. Most of the equations are
more complex than those just described.
Fig. 1: Inductor configurations.
$$ L = {N^2 \mu A \over l} \, \text{(henries, H)} \tag{1}$$
$$ L = {N^2 \mu_r \mu_o A \over l} = \mu_r {N^2 \mu_o A \over l} $$
$$L = \mu_r L_o \tag{2}$$
Example 1:
Find the inductance of the air-core coil of [Fig. 2].
Solution:
For air core coil:
Where
Therefore Eq. (i) becomes
Fig. 2: For Example 1.
$$ L_o= {N^2 \mu_o A \over l} \tag{i}$$
$$ \begin{split}
A &= {\pi d^2 \over 4} \\
&= {\pi \times (4 \times 10^{-3} m)^2 \over 4}\\
&=12.57 \times10^{-6} m^2\\
\end{split}$$
$$ \begin{split}
L_o &= {(100)^2 (4 \pi \times 10^{-7})(12.57 \times10^{-6} \over 0.1} \\
&= 1.58 \mu H
\end{split}$$
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