The 120-V dc source of Fig. 1(a) delivers 3.6 W to the load. Determine the peak value of the applied voltage (Em) and the current (Im) if the ac source Fig. 1(b) is to deliver the same power to the load.

realnfo

2021-10-29 12:50:43

$$P_{dc} = {V_{dc} I_{dc}}\\I_{dc} ={ P_{dc} \over V_{dc} } = {3.6W \over 120 V} = 30mA\\I_m = 1.414 I_{dc}\\ I_m = 1.414(30mA)\\ = 42.42mA\\$$

$$E_m = 1.414 E_{dc} = 1.414 (120) = 169.6V$$

realnfo

2021-10-29 12:59:39

$$P_{dc} = {V_{dc} I_{dc}}\\I_{dc} ={ P_{dc} \over V_{dc} } = {3.6W \over 120 V} = 30mA\\I_m = 1.414 I_{dc}\\ I_m = 1.414(30mA)\\ = 42.42mA\\$$

$$E_m = 1.414 E_{dc} = 1.414 (120) = 169.6V$$

realnfo

2021-10-29 13:02:11

$$P_{dc} = {V_{dc} I_{dc}}\\I_{dc} ={ P_{dc} \over V_{dc} } = {3.6W \over 120 V} = 30mA\\I_m = 1.414 I_{dc}\\ I_m = 1.414(30mA)\\ = 42.42mA\\$$

$$E_m = 1.414 E_{dc} = 1.414 (120) = 169.6V$$

realnfo

2021-10-29 13:06:19